Saturday, September 22, 2007

Egyptian geometry and other challenges: Let’s play math!

Egyptian geometry and other challenges: Let’s play math!:
FROM THE MOSCOW PAPYRUS 
(3) The area of a rectangle is 12, and the width is 3/4 of the length. How long are the sides of the rectangle?
The area of a rectangle equals length times width (l•w), which equals 12

(4) One leg of a right triangle is 2 1/2 times the other, and the area is 20. How long are the triangle’s sides?
The area of a triangle equals 1/2 of the base times the height (A=1/2 bh), which equals 20.

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5 comments:

  1. You're giving flashbacks to algebra one class last spring, we also did some geometry review.

    Alg 2 starts Tuesday yeehaw!

    Ha! ;)

    ReplyDelete
  2. Yeah!! "Gotta love math" is one of my favorite sayings!

    ReplyDelete
  3. Ummm, okay...I'll take your word for it.

    I'm more into literature myself so math is rather like a totally different language to me. Figures ain't really my forte.

    Yet, I have a couple of grandchildren who would regard your math as fun...can't understand it meself...

    ReplyDelete
  4. Thank you, I enjoyed the Egyptian geometry problems article.
    I would like to invite you to visit more geometry challenges at 52 geometry problems

    Antonio

    ReplyDelete

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